(y^2-y)/y^2-4y+3

Solution for (y^2-y)/y^2-4y+3 equation:

D( y )

y^2 = 0

y^2 = 0

y^2 = 0

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y in (-oo:0) U (0:+oo)

(y^2-y)/(y^2)-(4*y)+3 = 0

(y^2-y)/(y^2)-4*y+3 = 0

(y^2-y)/(y^2)+(-4*y*y^2)/(y^2)+(3*y^2)/(y^2) = 0

y^2-4*y*y^2+3*y^2-y = 0

y^2-4*y^3+3*y^2-y = 0

4*y^2-4*y^3-y = 0

4*y^2-4*y^3-y = 0

y*(4*y-4*y^2-1) = 0

4*y-4*y^2-1 = 0

DELTA = 4^2-(-4*(-1)*4)

DELTA = 0

y = -4/(-4*2)

y = 1/2 or y = 1/2

y*(y-1/2)^2 = 0

(y*(y-1/2)^2)/(y^2) = 0

(y*(y-1/2)^2)/(y^2) = 0 // * y^2

y*(y-1/2)^2 = 0

( y-1/2 )

y-1/2 = 0 // + 1/2

y = 1/2

( y )

y = 0

y in { 0} 

y in { 1/2, 1/2 }